Latent Heat Calculator
Calculate melting or boiling energy, specific latent heat, or mass changed with Q = mL. Get worked solution steps and a live phase-change diagram with all values displayed.
Latent Heat Phase-Change Diagram
Energy, mass, latent heat, state change and constant-temperature behaviour are visible in one chart.
Step-by-Step Solution
Here's exactly how this answer was calculated, one step at a time.
Given: Mass = 2 kg, heat energy = 668,000 J, latent heat = 334,000 J/kg
Step 1: Write the latent heat formula
Latent heat changes a material's state while its temperature stays constant.
Q = m × LStep 2: Use SI units
L = 334,000 J/kg; m = 2 kgStep 3: Substitute the known values
Q = 2 × 334,000Step 4: Calculate phase-change result
Q = 668,000 J
The latent heat calculation result is:
668,000 J
Free Latent Heat Calculator
This Latent Heat Calculator finds the energy needed to melt, freeze, boil or condense a substance, as well as specific latent heat or mass changed. Select a water fusion or vaporization preset, or enter a custom material value. The calculator applies Q = mL, converts results into joules and kilojoules, and explains every step. Its visual phase-change diagram shows the initial state, final state, mass, energy and latent-heat value directly.
It is helpful for thermodynamics homework, calorimetry questions, refrigeration examples and science revision. The calculation covers a phase change at constant temperature. If the substance also warms or cools before or after changing state, add sensible heat calculations with Q = mcΔT.
Latent Heat Formula: Q = mL
The latent heat equation is Q = m × L. Q is energy in joules, m is mass in kilograms, and L is specific latent heat in J/kg. Rearrange it to L = Q/m when finding the property of a material, or m = Q/L when finding how much material changes state.
The word latent means hidden. Energy is still transferred, but during the pure phase change it separates particles or reorganizes them instead of increasing average kinetic energy, so temperature does not rise.
Latent Heat of Fusion and Vaporization
Specific latent heat of fusion describes melting or freezing. Water's heat of fusion is approximately 334 kJ/kg: melting 2 kg of ice at 0°C needs Q = 2 × 334,000 = 668,000 J. Freezing releases the same magnitude of energy.
Specific latent heat of vaporization describes boiling or condensation. Water's value is about 2,256 kJ/kg at its boiling point, much larger than fusion. Boiling separates particles much more completely, so it needs much more energy than melting the same mass.
Latent Heat Worked Example
To boil 0.5 kg of water already at 100°C, use L = 2,256,000 J/kg. Q = mL = 0.5 × 2,256,000 = 1,128,000 J, or 1,128 kJ. The water remains at 100°C while it becomes steam at the same pressure.
If water begins at 20°C, first calculate energy to heat it to 100°C using Q = mcΔT, then calculate vaporization energy with Q = mL. Add both numbers. Separating these stages is the key to solving phase-change questions correctly.
Heating Curves and Energy Transfer
On a heating curve, temperature slopes upward while a single phase warms. Flat sections occur at melting and boiling points, where added heat produces a state change rather than a temperature rise. Cooling curves behave in reverse: energy is released during condensation and freezing at nearly constant temperature.
Pressure changes melting and boiling temperatures and can affect latent heat values. Use properties measured at the correct conditions for accurate technical work.
Applications, Units and Safety
Latent heat explains why steam burns are severe, why ice cools drinks, how refrigerators and heat pumps move energy, and why evaporating sweat cools skin. Use kilograms and J/kg. One kJ/kg equals 1,000 J/kg; use consistent units before multiplying.
Steam, boiling liquids, cryogenic materials and pressurized systems can be dangerous. This educational calculation does not provide a safe operating limit. Follow laboratory procedures, use appropriate protective equipment and rely on qualified engineering for practical equipment.
Latent Heat Calculator FAQ Summary
Use Q = mL only for state changes at constant temperature. Use Q = mcΔT for ordinary warming or cooling. In multi-stage questions, calculate each stage separately and add energies. Water has approximate Lf = 334 kJ/kg and Lv = 2,256 kJ/kg.
Frequently Asked Questions
What is the latent heat formula?
Q = mL, where Q is energy, m is mass and L is specific latent heat.
What is latent heat of fusion?
Energy needed per kilogram to melt a substance at its melting point, or released when it freezes.
What is latent heat of vaporization?
Energy needed per kilogram to boil a liquid, or released when vapour condenses.
Why is temperature constant during a phase change?
Energy changes particle arrangement and intermolecular bonding rather than average kinetic energy.
What are water's latent heat values?
Approximately 334 kJ/kg for fusion and 2,256 kJ/kg for vaporization.
Should I use Q = mcΔT while ice melts?
No. Use Q = mL during melting; use Q = mcΔT only before or after the phase change.
Can latent heat be negative?
Energy released in freezing or condensation can be represented as negative for the material.
Does pressure matter?
Yes. Pressure affects boiling point and can affect phase-change properties.