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Hess's Law Enthalpy Solver

Combine known reactions with reverse and multiplier controls to solve for a target reaction's ΔH, or switch to Standard Enthalpies of Formation mode with a built-in ΔHf° library. Full step-by-step working and diagrams included.

Known (given) reactions

Reaction 1
Reaction 2
Reaction 3
Enthalpy of target reaction, ΔH-74.8 kJ
Reaction typeExothermic — the reaction releases heat
Known reactions combined3

Contribution of Each Reaction

All values in kJ. Bars to the right of the centre line are positive; bars to the left are negative.

C(graphite) + O2(g) → CO2(g)-393.5 kJH2(g) + 1/2 O2(g) → H2O(l)-571.6 kJCH4(g) + 2 O2(g) → CO2(g) + 2 H2O(…890.3 kJΔH(target)-74.8 kJΔH(target) = Σ [multiplier × (±1) × ΔH(given reaction)] — bar length shows magnitude, not a fixed axis.

Step-by-Step Solution

Here's exactly how this answer was calculated, one step at a time.

Given: C(graphite) + 2 H2(g) → CH4(g)

  1. Step 1: Write the combination rule

    Reversing a reaction flips the sign of its ΔH; scaling a reaction multiplies its ΔH by the same factor.

    ΔH(target) = Σ [ multiplier × (±1) × ΔH(given reaction) ]
  2. Step 2: Reaction 1 — C(graphite) + O2(g) → CO2(g)

    1 × (-393.5 kJ) = -393.5 kJ
  3. Step 3: Reaction 2 — H2(g) + 1/2 O2(g) → H2O(l)

    2 × (-285.8 kJ) = -571.6 kJ
  4. Step 4: Reaction 3 (reversed) — CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l)

    1 × (−1) × (-890.3 kJ) = 890.3 kJ
  5. Step 5: Add every scaled reaction enthalpy together

    ΔH(target) = -393.5 + -571.6 + 890.3 = -74.8 kJ
  6. Step 6: Read the sign

    A negative ΔH means the target reaction releases heat (exothermic). A positive ΔH means it absorbs heat (endothermic).

    Exothermic — the reaction releases heat

The enthalpy of the target reaction is:

-74.8 kJ

Free Hess's Law Enthalpy Solver

Hess's Law lets you find the enthalpy change of a reaction without ever running it in a lab — as long as you already know the enthalpy of some other reactions that connect to it. This calculator gives you two ways to do that. The Combine Reactions tool lets you take two or more known reactions, flip the ones that need reversing, scale each one by whatever multiplier makes the atoms cancel out correctly, and add them up to get the ΔH of a target reaction you never had to test directly. The Standard Enthalpies of Formation tool does the same underlying math a different way, using tabulated ΔHf° values for every reactant and product in a balanced equation, with a built-in library of common compounds so you don't have to hunt through a textbook appendix.

Both tools show every step of the working, tell you straight away whether the reaction is exothermic or endothermic, and draw a simple bar chart so you can see where the final number actually comes from. Nothing here needs an account, a download, or any software — it runs right in your browser and updates the moment you change a number.

What Is Hess's Law?

Hess's Law says that the total enthalpy change of a reaction is the same no matter what route you take to get from the starting materials to the final products — one big step or several small ones, the total energy change comes out identical. This is true because enthalpy is what chemists call a state function: it only depends on where you start and where you end up, not on the path in between. Think of it like altitude on a hike. If you start at sea level and end up on a mountain summit at 3,000 metres, you've gained 3,000 metres of elevation whether you walked straight up a cliff face or took a winding trail — the path doesn't change the net change in height.

That single idea is what makes Hess's Law so useful. Some reactions are too slow to measure, too dangerous to run safely in a school lab, or produce a messy mix of side products that ruins a clean calorimetry reading. Hess's Law sidesteps all of that: as long as you can find, or already know, a set of other reactions that add up on paper to the reaction you actually care about, you can calculate its ΔH without ever mixing a single chemical.

Two Ways to Solve Hess's Law Problems

This calculator gives you both routes chemistry courses actually teach. Combine Reactions is the classic 'given three equations, find the fourth' style problem — you're handed a target reaction and a handful of other reactions with known ΔH values, and your job is to add, reverse, and scale those known reactions until they add up to the target. Standard Enthalpies of Formation skips the reaction-juggling entirely and goes straight to ΔH°rxn = ΣΔHf°(products) − ΣΔHf°(reactants), using published formation values for each substance. Switch between the two tabs at any time, whichever matches the problem sitting in front of you.

Combining Known Reactions: The Three Rules

When you combine reactions to build a target equation, three rules govern what you're allowed to do to each known reaction, and each one has a matching effect on its ΔH value.

  • Reverse a reaction, and you flip the sign of its ΔH. If a reaction releases 100 kJ going forward, running it backward absorbs 100 kJ.
  • Multiply a reaction by a whole number or a fraction, and you multiply its ΔH by that same number. Double the reaction, double the energy; halve it, halve the energy.
  • Add two or more reactions together, and you add their (possibly reversed, possibly scaled) ΔH values to get the ΔH of the combined reaction. Any species that appears as both a product and a reactant across the reactions you're adding cancels out completely, just like a term in an algebra equation.

Worked Example: Finding ΔH for the Formation of Methane

Say your target reaction is C(graphite) + 2 H2(g) → CH4(g), and you're given three known reactions: (1) C(graphite) + O2(g) → CO2(g), ΔH1 = −393.5 kJ; (2) H2(g) + 1/2 O2(g) → H2O(l), ΔH2 = −285.8 kJ; and (3) CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l), ΔH3 = −890.3 kJ.

To build the target, use reaction 1 as-is, double reaction 2 since the target needs 2 mol of H2, and reverse reaction 3 because CH4 needs to end up as a product, not a reactant. Adding the scaled values: ΔH = (1 × −393.5) + (2 × −285.8) + (−1 × −890.3) = −393.5 − 571.6 + 890.3 = −74.8 kJ. That result matches the accepted standard enthalpy of formation for methane almost exactly — this preset is loaded into the Combine Reactions tab by default, so you can see every line of that math worked out live.

Worked Example: Graphite to Diamond

Here's a shorter example that shows how just two reactions can answer a question you could never test directly, since graphite doesn't turn into diamond in a beaker. Given C(graphite) + O2(g) → CO2(g), ΔH1 = −393.5 kJ, and C(diamond) + O2(g) → CO2(g), ΔH2 = −395.4 kJ, you want C(graphite) → C(diamond). Reverse the second reaction so diamond ends up on the product side, then add: ΔH = −393.5 + 395.4 = 1.9 kJ. That small positive number tells you converting graphite into diamond takes a little energy in, which lines up with why diamond is the less stable, higher-energy form of carbon at everyday pressure. Load this example from the dropdown to see it solved step by step.

Standard Enthalpies of Formation: ΔH°rxn = ΣΔHf°(products) − ΣΔHf°(reactants)

The formation-value method skips the reaction-combining puzzle and goes straight to the source. Every substance has a standard enthalpy of formation, ΔHf°, defined as the enthalpy change when exactly one mole of that substance is made from its elements in their standard states. Multiply each species' ΔHf° by its coefficient in the balanced equation, add up the product side, add up the reactant side, and subtract: ΔH°rxn = ΣΔHf°(products) − ΣΔHf°(reactants).

One detail trips a lot of students up the first time: any element sitting in its normal, stable form — O2 gas, N2 gas, solid graphite, liquid mercury — has a ΔHf° of exactly zero. That's not a coincidence; it's the definition. Forming an element from itself takes no energy, so the reference point is set at zero. This calculator's built-in library already has that covered for over twenty common elements and compounds, so you can pick a species from the list and its ΔHf° fills in automatically instead of you having to look it up.

Worked Example: Combustion of Methane Using ΔHf° Values

Take CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l). Using ΔHf°[CH4(g)] = −74.8 kJ/mol, ΔHf°[O2(g)] = 0 kJ/mol, ΔHf°[CO2(g)] = −393.5 kJ/mol, and ΔHf°[H2O(l)] = −285.8 kJ/mol, the product side totals (1 × −393.5) + (2 × −285.8) = −965.1 kJ, and the reactant side totals (1 × −74.8) + (2 × 0) = −74.8 kJ.

ΔH°rxn = −965.1 − (−74.8) = −890.3 kJ per mole of methane burned, the exact same −890.3 kJ used as a given value in the Combine Reactions example above. That's not a coincidence either — it's Hess's Law proving itself, since both methods are really just two different accounting systems for the same underlying energy change.

How to Use This Calculator

On the Combine Reactions tab, either load one of the built-in example problems from the dropdown to see a fully worked solution, or clear it and build your own: type in each known reaction's ΔH, set the multiplier needed to balance it against your target, and tick 'Reverse this reaction' for any reaction that has to run backward. Add up to six known reactions if your problem needs them.

On the Standard Enthalpies of Formation tab, list every reactant and product with its coefficient from the balanced equation, and either type in its ΔHf° directly or pick it from the quick-fill library if it's a common substance. Either tab updates its result, reaction-type label, and bar chart instantly, and the full step-by-step working is always one click away.

Why Hess's Law Works: Enthalpy as a State Function

Not every quantity in chemistry behaves this way — the work done and the heat released while a reaction is happening can both depend heavily on exactly how the reaction was run, what apparatus was used, and how fast it went. Enthalpy is different because at constant pressure, it only cares about the starting condition and the finishing condition of the system, not the road taken between them. That's the whole reason you're allowed to chop a reaction into imaginary intermediate steps, look up or measure the enthalpy of each step separately, and simply add them together to get the real answer — the outcome doesn't depend on which path you 'chose' on paper, only on where you started and where you ended.

Common Mistakes When Applying Hess's Law

A few errors show up again and again in Hess's Law problems, and this calculator is built to help you catch them.

  • Forgetting to flip the sign of ΔH when a reaction is reversed — reversing always changes the sign, never the magnitude.
  • Multiplying the coefficients in a reaction without also multiplying its ΔH by the same factor.
  • Mixing up which species need to cancel — check that every intermediate substance appears in exactly matching amounts on opposite sides once all the reactions are combined, or it won't cancel out cleanly.
  • Using ΔHf° values from mismatched physical states — H2O(l) and H2O(g) have very different formation enthalpies, so the state (solid, liquid, gas, aqueous) always has to match the actual equation.
  • Dropping a negative sign when subtracting the reactant total from the product total in the ΔH°rxn formula.

Real-World Uses of Hess's Law

Hess's Law isn't just a paper exercise for chemistry class. Engineers use it to work out how much heat a large-scale industrial reaction will release before ever running it at full size, which matters for reactor safety and cooling system design. Fuel and energy companies use formation enthalpies to compare how much usable energy different fuels actually deliver per mole or per kilogram. Materials scientists use the same graphite-to-diamond style logic to predict the stability of one crystal form of a substance against another, and pharmaceutical chemists rely on it to estimate the heat released during a synthesis step long before they scale a reaction up from a small lab flask to a full production batch.

Limitations to Keep in Mind

The Combine Reactions method is only as good as the known ΔH values you feed it — a small measurement error or a typo in any one of the given reactions carries straight through to the final answer, so it's worth double-checking every value against a reliable source. The Standard Enthalpies of Formation method assumes standard conditions, 25°C and 1 atm, for every species involved; real industrial reactions rarely run at exactly those conditions, so ΔH°rxn is best treated as a very close estimate rather than an exact prediction for a process running at, say, 300°C under high pressure.

Quick Reference: Formulas on This Page

ΔH(target) = Σ [multiplier × (±1) × ΔH(given reaction)] — reverse a reaction to flip its sign, scale it to multiply its ΔH. ΔH°rxn = ΣΔHf°(products) − ΣΔHf°(reactants) — Hess's Law built from standard enthalpies of formation. ΔHf° of any element in its standard state = 0 kJ/mol, by definition.

Frequently Asked Questions

What is the formula for Hess's Law?

Hess's Law itself isn't one single formula — it's the rule that lets you add up known reactions, each scaled and reversed as needed, to get ΔH(target) = Σ[multiplier × (±1) × ΔH(given)]. When you're working from tabulated formation values instead, the matching formula is ΔH°rxn = ΣΔHf°(products) − ΣΔHf°(reactants).

How do you know when to reverse a reaction?

Look at where each species needs to end up in your target reaction. If a substance sits on the reactant side of a known reaction but needs to be a product in your target, or the other way around, reverse that known reaction and flip the sign of its ΔH.

Can the multiplier be a fraction, not just a whole number?

Yes. Fractional multipliers like 1/2 or 1/3 are completely normal in Hess's Law problems, especially when balancing an odd number of atoms such as oxygen. This calculator accepts decimals in the multiplier field, so 1/2 can be entered as 0.5.

What's the difference between the two calculator modes?

Combine Reactions solves the 'given these reactions, find the target' style of problem by adding, reversing, and scaling whole equations. Standard Enthalpies of Formation solves the same kind of question a different way, by summing tabulated ΔHf° values for every substance in one balanced equation directly.

Why is the standard enthalpy of formation of an element zero?

By definition. ΔHf° is the energy needed to form one mole of a substance from its elements in their normal, stable states, and forming an element from itself takes no net energy, so the reference value is set at exactly zero.

Do all the intermediate substances have to cancel out completely?

Yes. For the combined equation to actually equal your target reaction, every species that isn't in the target itself has to appear in identical amounts on both sides once you add the scaled reactions together, so it cancels out.

Is Hess's Law only used for enthalpy?

Hess's Law is most commonly taught with enthalpy, but the same state-function logic applies to any property that depends only on the starting and ending state of a system, such as entropy and Gibbs free energy.

How accurate are Hess's Law calculations compared to direct measurement?

Very close, as long as the ΔH or ΔHf° values going in are accurate and the physical states of every species match the real reaction. Small differences usually come from real-world heat loss during direct calorimetry, not from any flaw in Hess's Law itself.

Can I combine more than two or three known reactions?

Yes — this calculator supports up to six known reactions in the Combine Reactions tab, which covers the large majority of textbook and real-world Hess's Law problems.

What units does this calculator use for ΔH?

Kilojoules (kJ) per mole of reaction as written, matching the units almost every general chemistry textbook and standard reference table uses for both reaction enthalpies and formation enthalpies.